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0.0027x^2-0.216x+4.05=0
a = 0.0027; b = -0.216; c = +4.05;
Δ = b2-4ac
Δ = -0.2162-4·0.0027·4.05
Δ = 0.002916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.216)-\sqrt{0.002916}}{2*0.0027}=\frac{0.216-\sqrt{0.002916}}{0.0054} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.216)+\sqrt{0.002916}}{2*0.0027}=\frac{0.216+\sqrt{0.002916}}{0.0054} $
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